Prove that the square of any positive integer is either of the form 5m or 5m+1 or 5m+4 for some integer q
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Step-by-step explanation:
Consider that m=2.square of 2=4, (2×2=4).
5m=5 (2)=10
4 not equals to 10
5m+1=5 (2)+1=11
4 not equals to 11
5m+4=5 (2)+4=14
14 is also not equals to 4.
If we take 5 as "m" then the square of 5=25,which satisfies the condition 5m
hence proved.
only 5 is the number which can satisfies the condition 5m. There is no other number which can satisfies the conditions 5m,5m+1,5m+4.
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