Prove that the square of any positive integer of the form 5q + 1 is of the same form.
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SOLUTION :
Since positive integer n is of the form 5q + 1
Let n = 5q + 1, then
n² = (5q + 1)²
[On squaring both sides]
n² = (5q)² + 2(1) (5q) + 1²
[(a+b)² = a² + b² + 2ab]
n² = 25q² + 10q + 1
n² = 5(5q² + 2q)+1
n² = 5m + 1, where m = 5q² + 2q
Hence n² is of the form 5m + 1.
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Answered by
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hello mate
here is your prooving
for any postive integer is in the form of 5q+1
sqauring the no. (5q +1)^2 = 25 q2 + 10 q +1
-----------> 5 (5 q2 + 2q ) +1
-----------> 5 m +1 .( where m is the value of any positive integer = 5q2 + 2q )
hope this would help you
here is your prooving
for any postive integer is in the form of 5q+1
sqauring the no. (5q +1)^2 = 25 q2 + 10 q +1
-----------> 5 (5 q2 + 2q ) +1
-----------> 5 m +1 .( where m is the value of any positive integer = 5q2 + 2q )
hope this would help you
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