Question

Prove that the squares f the sequence 1,3,5...belongs to that sequence itself

Answer 1

Answer:

Answer:

99

Step-by-step explanation:

The sequence is arithmatic progression.

First term is 1, Common Difference is 2

Using the formula

Tn term= first term + (number of term to be found - 1)* Common difference

T50= 1+(50-1)*2

T50= 1+(49)*2

T50= 1+98

T50= 99

Therefore, the 50th term is 99.

Answer 2

Answer:

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