Question

Prove that the straight line drawn from the centre of a circle to bisect
a chord which is not a diameter is perpendicular to the chord.​

Answer 1

Answer:

AB is chord of circle & OX bisects AB i.e. AX = BX.

Step-by-step explanation:

To Prove : OX ⊥ AB Proof : In ∆AOX & ∆BOX OA = OB OX = OX AX = BX ∴ ∆AOX ≅ ∆BOX ∠ AXO