Prove that the straight lines whose direction cosines are given by the relation al+bm+cn=0 and fmn+gnl+hlm=0 are perpendicular, if
f/a + g/b + h/c = 0.
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08-Mar-2015 · 1 post · 1 author
=>n=-(al+bm)/c. Substituting this value of n in eq fmn+ gnl+hlm=0 ... =>(f/a)+(g/b) +(h/c) =0 This is the required condition. Thanks .
=>n=-(al+bm)/c. Substituting this value of n in eq fmn+ gnl+hlm=0 ... =>(f/a)+(g/b) +(h/c) =0 This is the required condition. Thanks .
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