prove that the sum of a rational number and an irrational no is an irrational no
Answers
Answer:
Step-by-step explanation:
Assume that a is rational, b is irrational, and a+b is rational. Since a and a+b are rational, we can write them as fractions.
Let a = c/d
And a + b = m/n
Substituting a = c/d in a + b = m/n gives the following:
c/d + b = m/n
Now, let's subtract c/d from both sides of the equation.
b = m/n - c/d
or, b = m/n + (-c/d)
Since the rational numbers are closed under addition, b = m/n + (-c/d) is a rational number. However, the assumptions said that b is irrational, and b cannot be both rational and irrational. This is our contradiction, so it must be the case that the sum of a rational and an irrational number is always irrational.
Hope it helps you :)
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Step-by-step explanation:
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