prove that the sum of a two digit number 36 and on reversing the number is exactly divisible by 11
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Step-by-step explanation:
Let digit at ones place be 1
then digit at tens place is 1*10 = 10
Rrequired no. = 10 + 1 = 11
New no. formed by interchanging the digit =(1*10) + 1 =11
Now,
Dividing new no. formed by 11
11/11
since,it is divisible
Hence,proved
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