Prove that the sum of all angles of a quadrilateral is 360°(therem)
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If we draw one diagonal to quadrilateral we will get two triangles i.e. △ABC and △ACD and we know that sum of the angles of a triangle is 180°
Sum of angles of quadrilateral ABCD=sum of angles of △ABC + sum of the angles △ACD
= 180°+180°
=360°
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