prove that the sum of all angles of a regular hexagon is 720
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In the given image the hexagon is divided into 2 triangles and one quadrilateral.
as we know that
sum of all angles of a triangle equals 180°
and sum of all angles of a quadrilateral equals 360°
all angles of triangle AFB + all angles of quadrilateral BFEC + all angles of triangle EDC = sum of all angles of hexagon ABCDEF
= 180° +360° + 180°
= 720°.
Thus, proved that sum of all angles of a hexagon equals 720°.
as we know that
sum of all angles of a triangle equals 180°
and sum of all angles of a quadrilateral equals 360°
all angles of triangle AFB + all angles of quadrilateral BFEC + all angles of triangle EDC = sum of all angles of hexagon ABCDEF
= 180° +360° + 180°
= 720°.
Thus, proved that sum of all angles of a hexagon equals 720°.
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this is the most easiest way
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