Question

prove that " THE SUM OF ALL INFERIOR ANGLRS OF A TRIANGLE IS 180°

Answer 1

$\textbf{Used Formula : ( n - 2 ) } \times 180°$

n = Number of sides,







In ∆ , Number of sides = 3



Hence,

Sum of all angles = ( 3 - 2 ) × 180°

Sum of all angles = 1 × 180°

Sum of all angles = 180°

Answer 2

Here how we can prove it. And this is how the formula, (n-2)×180 is derived.

(n-2)×180
=(3-2)×180
=1×180
=180°

Look at the picture: