Prove that the sum of all sides of a triangle is greater than the sum of the medians
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Answer:
For a triangle ABC,draw its medians namely AM, BN, and CO.
Step-by-step explanation:
Now I triangle AMC, AC+MC>AM by side sum property of triangle.
Similarly prove that BN and CO are smaller than respective sums of the other two sides of the triangle.
By all we get the result.
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