prove that the sum of all the exterior angle of a triangle is 720 degree.
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it is always 360° for any polygon. so this can't be proved.
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Question-
Prove that the sum of the exterior angles of a triangle is equal to 360 degrees.
Answer-
Let us say, ∠1, ∠2 and ∠3 are the interior angles of a triangle. When we extend the sides of the triangle in the outward direction, then the three exterior angles formed are ∠4, ∠5 and ∠6, which are consecutive to ∠1, ∠2 and ∠3, respectively.
Hence,
- ∠1 + ∠4 = 180° ……(i)
- ∠2 + ∠5 = 180° …..(ii)
- ∠3 + ∠6 = 180° …..(iii)
If we add the above three equations, we get;
∠1+∠2+∠3+∠4+∠5+∠6 = 180° + 180° + 180°
Now, by angle sum property we know,
∠1+∠2+∠3 = 180°
Therefore,
180 + ∠4+∠5+∠6 = 180° + 180° + 180°
⇒ ∠4+∠5+∠6 = 360°
This proves that the sum of the exterior angles of a triangle is equal to 360 degrees.
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