prove that the sum of all the three angles of triangles is 180 degrees
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Answered by
13
Answer:
FROM Δ ABC
draw a parallel line DE ║ BC
∠DAB + ∠BAC +∠CAE = 180
∠DAB = ∠ABC (ALTERNATE ANGLES ARE EQUAL)
∠CAE = ∠ACB (ALTERNATE ANGLES ARE EQUAL)
SO, ∠ABC + ∠ACB + ∠BAC =180.
⚡Hope it will help you.⚡
Answered by
1
Answer:
answer refer to the attachment.
see the attachment mate
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