prove that the sum of angles of a triangle is 180 degree
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We draw a line parallel to AB that passes
through point C.
Angles C and C' are vertical angles,
therefore ∠C = ∠C'.
Angles B and B' are corresponding angles,
therefore ∠B = ∠B'.
Angles A and A' are corresponding angles, therefore ∠A = ∠A'.
So, the angle sum ∠A + ∠B + ∠C is equal to the angle sum ∠A' + ∠B' + ∠C'.
The three angles A', B', and C' form together a straight angle (they are along the line l).
So, their angle sum is 180°. But then the angle sum ∠A + ∠B + ∠C must also be 180
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Answer:
x + x + x = 180
Step-by-step explanation:
3 x = 180
x = 180 ÷ 3 = 60
x = 60
if take as a polygon
n - 2 × 180 = 3 - 2 × 180
= 1 × 180 = 180
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