Question

prove that the sum of any real number and its reciprocal cannot be equal to 3/2.​

Answer 1

Step-by-step explanation:

 number be ′a′.

Thus, we have

a+a1=1225

⇒12(a2+1)=25a

⇒a2−25a+12=0

⇒12a2−16a−9a+12=0

⇒4a(3a−4)−3(3a−4)=0

⇒(3a−4)(4a−3)=0

⇒a=34 or a=43

(b) Let the positive number be d, then its reciprocal will be d1.

Now, we have

d+d1≥2

d2+1≥2d

d2−2d+1≥0

(d−1)2≥0

⇒d≥1

Answer 2

Answer:

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