prove that the sum of any sides of a triangle is greater than the third side .. don't dare to spam ..
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In ΔABC, extend AB to D in such a way that AD=AC.
In ΔDBC, as the angles opposite to equal sides are always equal, so,
Therefore,
As the sides opposite to the greater angle is longer, so,
Hence, sum of two sides of a triangle is always greater than the third side.
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