Question

prove that the sum of any two sides of a triangle is greater than the third side.

Answer 1

let , a triangle ABC IN WHICH
ANGLE A =6O
ANGLE B=6O
ANGEL C=6O
(by angle sum property)
now
add angle A and angle B ( 60 add 60 =120).....1
add angle B and angle C(60 add 60 =120)......2
add angle c and angle a (60 add 60= 120)....
.3 .Here IN the sum of all the 3 WE observed that sum of two is greater than the 3rd.
FROM 1 , 2, AND 3 WE CONCLUDE THAT SUM OF TWO ANGLE IS GREATER THAN THE THIRD .
BY SROUSHAN11 I HOEP IT WILL HELP UUU

Answer 2

Hey mate your answer is attached above!!☺