Prove that the sum of any two sides of a triangle is greater than twice the length of median drawn to the third side
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conside a triangle ABC having sides..
AB = 4cm
BC = 5 cm
CA = 6 cm
if you will add any two sides then obviously sum will be greater than other side.m
AB + BC = 4+5= 9cm > AC = 6cm
AB + CA=6 + 4=10CM >BC = 5 cm
BC + CA = 5+6 = 11cm > AB=4cm..
HENCE PROVED.
AB = 4cm
BC = 5 cm
CA = 6 cm
if you will add any two sides then obviously sum will be greater than other side.m
AB + BC = 4+5= 9cm > AC = 6cm
AB + CA=6 + 4=10CM >BC = 5 cm
BC + CA = 5+6 = 11cm > AB=4cm..
HENCE PROVED.
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