Question

Prove that the sum of cubes of three consecutive natural numbers
is always divisible by 3.
​

Answer 1

Answer:

8+9+10

Step-by-step explanation:

Three consecutive natural number

1,2,3

1+2+3=6

Cube root of 6 is 2 so it is not divisible by 3

Let's take 8+9+10=27

Cube root of 27 is 3. so 3 is divisible by 3.