prove that the sum of either pair of opposite angles of a cyclic quadrilateral is 180 degree using the above find X and Y . Pls do it fast the equations are x+y,2x,5x-y and x+2y first fig
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PS: the figure is not clear
u can solve it by adding the opp angle nd equating to 180
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Answer:
The value of x=40° and y=30°.
Step-by-step explanation:
As per the data given in the question,
Draw a diameter on a cirlce, and extend 2 triangles on the perimeter on opposite side having base at diameter.
As we know that angle subtended by diameter on perimeter is right angle =
So, sum of opposite angles become
Now, in the question,
∠A+∠C=180° (opposite angles of cyclic quad.)
∠B+∠D=180° (opposite angles of cyclic quad.)
As given in figure
x+2y+2x = 180
3x+2y =180 ..........(1)
5y-x+x+y = 180
6y=180
y=30 ............(2)
Putting value of y in (1)
3x+ 60 =180
3x = 120
x= 40
The value of x=40° and y=30°.
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