prove that the sum of first n even number= n(n+1)
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Answered by
0
Answer:
2n+n
Step-by-step explanation:
n(n+1)
n×n+n×1
2n+n
Answered by
4
Step-by-step explanation:
even numbers are 2 ,4 ,6 ,..........
here , first term,a = 2
common difference,d = 2
Sn = n/2 [ 2a + (n-1)d ]
= n/2 [ 4 + (n-1) 2 ]
= n [ 2 + n- 1]
= n( n+1)
I HOPE THIS MAY HELP YOU
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