Prove that the sum of four angles of a quadrilateral ABCD is 360°.
(Hint: Draw diagonal BD by joining the points B and D and use angle sum property of a triangle for two triangles
formed.]
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Answer is literally in the Hint
BDC is a triangle so it's 180 degree
Similarly BDA is also triangle it's also 180 degree
BDC+BDA=180+180=360 degree
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