Question

Prove that the sum of interior angles of an octagon is twice the sum of the interior angles of a pentagon

Answer 1

Answer:

sum lf interior angle of any regular polygon can be given by

180(n - 2)180(n−2)

where n is the no. of sides of polygon

for pentagon

n = 5

so sum of all interior angles is

180[5-2]

180(3)

540°

and for octagon

n = 8

so sum of interior angles is

180(8-2)

180(6)

1080° = 2(540)..