Prove that the sum of interior angles of any polygon with n sides is =(n-2)π.( No useless answers please)
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equal. Therefore, each interior angle = (2n−4)×90°n. 2. A quadrilateral is a polygon for which n = 4.
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Sum of the Interior Angles of an n-sided Polygon.
rkcomp31:
I said to prove the formula sum of angles=(n-2)π
Answered by
2
Answer:
In a regular polygon of n sides, all angles are equal. Therefore, each interior angle = (2n−4)×90°n. 2. A quadrilateral is a polygon for which n = 4.
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