Question

Prove That the sum of m. AM between any two number is to the sum of n AM between them as m:n?

Answer 1

Let the no. be= a, b

The sum of m AMs between a and b
=m (AM between a and b) = m (a+b/2)

The sum of n AMs between a and b 
=n (AM between a and ) = n (a+b/2)

sum of m AMs/sum of n AMs= m(a+b/2) /n(a+b/2)

=m/n

Answer 2

Answer:

m/n is answer

Step-by-step explanation:

Let the number be a, b

1)the sum of m AM's between a and b is

m(a+b)/2-(1)

2)the sum of n AM's between a and b is

n(a+b)/2-(2)

From 1 and 2

answer is m/n