Prove That the sum of m. AM between any two number is to the sum of n AM between them as m:n?
Answers
Answered by
65
Let the no. be= a, b
The sum of m AMs between a and b
=m (AM between a and b) = m (a+b/2)
The sum of n AMs between a and bÂ
=n (AM between a and ) = n (a+b/2)
sum of m AMs/sum of n AMs= m(a+b/2) /n(a+b/2)
=m/n
The sum of m AMs between a and b
=m (AM between a and b) = m (a+b/2)
The sum of n AMs between a and bÂ
=n (AM between a and ) = n (a+b/2)
sum of m AMs/sum of n AMs= m(a+b/2) /n(a+b/2)
=m/n
Answered by
6
Answer:
m/n is answer
Step-by-step explanation:
Let the number be a, b
1)the sum of m AM's between a and b is
m(a+b)/2-(1)
2)the sum of n AM's between a and b is
n(a+b)/2-(2)
From 1 and 2
answer is m/n
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