Math, asked by prateek1234567, 1 year ago

Prove that the sum of 'n' terms of an A.P., whose 1st term is 'a' and common difference is 'd' is given by Sn= n/2[2a+(n-1)d]

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Answered by prem134
2
the nth term of A.P is a+(n-1)d.Let s denote first n terms and reverse it and solve two equations
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prem134: its ok
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