Question

prove that, the sum of squares drawn on the sides of a rhombus is equal to the sum
of squares drawn on two diagonals.​

Answer 1

Step-by-step explanation:

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A rhombus ABCD whose diagonals AC and BD intersect at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus bisect each other at right angles. ... [ In a rhombus , all sides are equal ]

Answer 2

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