Math, asked by sanjanaparteki05, 9 months ago

Prove that the sum of squares on the sides of a rhombus is equal to the sum of squares on its

diagonal.​

Answers

Answered by Anonymous
5

Answer:

Given :- A rhombus ABCD whose diagonals AC and BD intersect at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus bisect each other at right angles. ... [ In a rhombus , all sides are equal

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