prove that the sum of the angle of a quadrilateral is 360°
Answers
Answered by
13
GIVEN-
ABCD is a quadrilateral
TO PROVE-
A+B+C+D=360
CONSTRUCTION -
Diagonal AC is drawn
PROOF -
triangles ABC&ADC are formed due to construction
we know that sum of all angles of triangle is 180
so
180+180=360
so sum of all angles of quadrilateral is 360
PROVED
ABCD is a quadrilateral
TO PROVE-
A+B+C+D=360
CONSTRUCTION -
Diagonal AC is drawn
PROOF -
triangles ABC&ADC are formed due to construction
we know that sum of all angles of triangle is 180
so
180+180=360
so sum of all angles of quadrilateral is 360
PROVED
Answered by
27
Consider a quadrilateral ABCD.
Draw a diagonal AC.
It forms two triangles ΔABC, ΔADC.
Let the angles in the triangles are 1 , 2 , 3 , 4 , 5 , 6 .
We know that :
1 + 2 + 3 = 180 ( Angle-Sum property)
4 + 5 + 6 = 180 ( Angle sum property)
Now,
1 + 2 + 3 + 4 + 5 + 6 = A + B + C + D
2 ( 180 ) = A + B + C + D
A + B + C + D = 360° .
Hence, proved that Sum of angles in a quadrilateral = 360°
Draw a diagonal AC.
It forms two triangles ΔABC, ΔADC.
Let the angles in the triangles are 1 , 2 , 3 , 4 , 5 , 6 .
We know that :
1 + 2 + 3 = 180 ( Angle-Sum property)
4 + 5 + 6 = 180 ( Angle sum property)
Now,
1 + 2 + 3 + 4 + 5 + 6 = A + B + C + D
2 ( 180 ) = A + B + C + D
A + B + C + D = 360° .
Hence, proved that Sum of angles in a quadrilateral = 360°
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