prove that the sum of the angle of a triangle is 180 decree
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Step-by-step explanation:
To prove this we are given a triangle PQR and Angle 1, Angle 2 and Angle 3 are the angles of triangle PQR.
To prove Angle 1 + A angle 2 + Angle 3 = 180 degree, draw a line XYP parallel to QR through the opposite vertex P.
XPY is a line,
Therefore, Angle 4 + Angle 1 + angle 5 = 180 degree (1)
XPY || QR and PQ,PR are transversals
Angle 4 = Angle 2 &
Angle 5 = Angle 3 ( Pairs of alternate angles)
Substituting Angle 4 and Angle 5 in (1) we get
Angle 2 + Angle 1 + Angle 3 = 180 degree
i.e. Angle 1 + Angle 2 + Angle 3 = 180 degree
Hope it helps :)
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