Prove that the sum of the angles of a quadrilateral is 360 degree .
Answers
Answer:
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Proof: In the quadrilateral ABCD,
∠ABC, ∠BCD, ∠CDA, and ∠DAB are the internal angles.
AC is a diagonal
AC divides the quadrilateral into two triangles, ∆ABC and ∆ADC
We have learned that the sum of internal angles of a quadrilateral is 360°, that is, ∠ABC + ∠BCD + ∠CDA + ∠DAB = 360°.
let’s prove that the sum of all the four angles of a quadrilateral is 360 degrees.
We know that the sum of angles in a triangle is 180°.
Now consider triangle ADC,
∠D + ∠DAC + ∠DCA = 180° (Sum of angles in a triangle)
Now consider triangle ABC,
∠B + ∠BAC + ∠BCA = 180° (Sum of angles in a triangle)
On adding both the equations obtained above we have,
(∠D + ∠DAC + ∠DCA) + (∠B + ∠BAC + ∠BCA) = 180° + 180°
∠D + (∠DAC + ∠BAC) + (∠BCA + ∠DCA) + ∠B = 360°
We see that (∠DAC + ∠BAC) = ∠DAB and (∠BCA + ∠DCA) = ∠BCD.
Replacing them we have,
∠D + ∠DAB + ∠BCD + ∠B = 360°
That is,
∠D + ∠A + ∠C + ∠B = 360°.
Or, the sum of angles of a quadrilateral is 360°. This is the angle sum property of quadrilaterals
HEY MATE!
I'm Sneha Bajaj and the answer u want is given below:-
Q1:-Prove that the sum of the angles of a quadrilateral is 360 °
Ans:
GIVEN:-
ABCD is a quadrilateral with 4 sides
WE HAVE TO PROVE:-
Sum of angles is of a quadrilateral is 360° also known as angle sum property of quadrilateral
CONSTRUCTION :-
Draw a line AC in the quadrilateral ABCD
PROOF:-
As we know sum of all angles of a triangle Δ is 180° then,
ΔADC + ΔABC= ABCD
180°+180°= ABCD
360° = ABCD