prove that the sum of the angles of the quadrilateral is 360°
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1) If we draw one diagonal to quadrilateral we will get two triangles. i.e. △ ABC and △ ACD
But we know that sum of angles of triangle is 180°
Sum of angles of quadrilateral ABCD = sum of angles △ ABC + sum of angles △ ACD
⇒ 180° + 180°
⇒ 360°
Hence, It is Proved..!!
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2) Consider △ ABC We can write it as
∠CAB + ∠B + ∠BCA = 180° …….. (1)
Consider △ ACD We can write it as
∠DAC + ∠ACD + ∠D = 180° ……… (2)
Adding equations (1) and (2) we get
∠CAB + ∠B + ∠BCA + ∠DAC + ∠ACD + ∠D = 180° + 180°
So we get
∠CAB + ∠DAC + ∠B + ∠BCA + ∠ACD + ∠D = 360°
So it can be written as
∠A + ∠B + ∠C + ∠D = 360°
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