Question

Prove that the sum of the exterior angles is 360° in the case of a
(i) triangle
​

Answer 1

Step-by-step explanation:

Answer 2

Step-by-step explanation:

prove- let in traingleABC, angle ABD is an exterior angle. angle ACE is an exterior angle.

then, angle ABC+ angle ABD.= 180 due to linear pair.

then, angle ACB + angle ACE = 180 due to linear pair.

then, angle BAC + angle CAF= 180 same by linear pair.

when we adding three angles

then, we get angle ABC+ angleABD + angle ACB + angle ACE + angle BAC + angle CAF = 180+ 180+ 180= 540.

here we start to do set as a forming traingle.

so, angle ABC + angle ACB + angle BAC ( can form a traingle of ABC) + angle ABD+ angle ACE + angle CAF = 540.

in the place of writing the sum of traingle as written above .

so, 180+ angle ABD + angle ACE + angle CAF= 540.

angle ABD + angle ACE + angle CAF = 540 - 180 = 360.

Hence it is proved as given in question.