prove that the sum of the interior angle of a Trapezium is 360 degree
Answers
Answered by
2
Sum of interior angles of closed polygon=(n-2)*180°
n=no of sides of polygon
In this case i.e is trapezium have four
Side therefore sum of its interior angles=(4-2)*180°=360°
Pls mark answer brainleast
n=no of sides of polygon
In this case i.e is trapezium have four
Side therefore sum of its interior angles=(4-2)*180°=360°
Pls mark answer brainleast
arvind74:
bad
What wrong in it
it is wrong because 4 is not mentioned
Trapezium is a quadrilateral and quadrilateral is a closed polygon up of four side ok foolish
if you are heart soory. but its wrong checking carefully
can you got my notification
Answered by
0
let ABCD is a trapezium and AB║CD
take AD as transversal line and we know Ab║CD So,
∠BAD + ∠CDA = 180° ------(1) (consecutive interior angle)
and
take BC as transvesal line and we know AB║CD So,
∠ABC + ∠BCD =180° --------(2) (consecutive interior angle)
add equation 1 and 2 we get
∠ABC +∠BCD + ∠BAD + ∠CDA =360°
hence,
the sum of all angles of trapezium is 360° (hence proved)
take AD as transversal line and we know Ab║CD So,
∠BAD + ∠CDA = 180° ------(1) (consecutive interior angle)
and
take BC as transvesal line and we know AB║CD So,
∠ABC + ∠BCD =180° --------(2) (consecutive interior angle)
add equation 1 and 2 we get
∠ABC +∠BCD + ∠BAD + ∠CDA =360°
hence,
the sum of all angles of trapezium is 360° (hence proved)
its best
Similar questions