prove that the sum of the interior angle of an octagon is twice the sum of the interior angle of Pentagon
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Sum of int. angles for n-gon is (n-2)×180
For pentagon, = (5-2)×180
For octagon, = (8-2)× 180
Ratio of sum of int angles= (8-2)×180 / (5-2)×180
6×180 / 3× 180
= 2/1
= 2
Proved.
For pentagon, = (5-2)×180
For octagon, = (8-2)× 180
Ratio of sum of int angles= (8-2)×180 / (5-2)×180
6×180 / 3× 180
= 2/1
= 2
Proved.
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