prove that the sum of the interior angles of an octagon is twice the sum of the interior angle of a Pentagon
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Step-by-step explanation:
Prove that the sum of the interior angle of an octagon is twice the sum of the ... For pentagon, = (5-2)×180. For octagon, = (8-2)× 180. Ratio of sum of int angles= (8-2)×180 / (5-2 ...
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Answer:
Sum lf interior angle of any regular polygon can be given by
where n is the no. of sides of polygon
for pentagon
n = 5
so sum of all interior angles is
180[5-2]
180(3)
540°
and for octagon
n = 8
so sum of interior angles is
180(8-2)
180(6)
1080° = 2(540)
please mark it as brainliest
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