Prove that the sum of the measures of the interior angles of a triangle is 180°
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heya mate
here is your answer
let
ab //cd and ec is their transversal the 4 = 1 (alternative interior angles )
and also let ab // cd and ed is their transversal then 3 = 5 ( alternative interior angles )
we know that sum of angles at a point is 180*
then 1 + 2 + 3 = 180*
as above 1 = 4 and 3 = 5
so now 4 + 2 + 5 = 180*
4 , 2 and 5 are interior angles of a triangle
hence proved
i hope it helped uh !!
thanks !!
here is your answer
let
ab //cd and ec is their transversal the 4 = 1 (alternative interior angles )
and also let ab // cd and ed is their transversal then 3 = 5 ( alternative interior angles )
we know that sum of angles at a point is 180*
then 1 + 2 + 3 = 180*
as above 1 = 4 and 3 = 5
so now 4 + 2 + 5 = 180*
4 , 2 and 5 are interior angles of a triangle
hence proved
i hope it helped uh !!
thanks !!
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