Question

Prove that the sum of the opp angles of a cyclic quad is 180 degree

Answer 1

$answer$

Proof - OB & OD

angleBOD = angle2BOD

angleBAD = angle1/2 BOD

Same as

angleBCD = angle1/2 DOB

angle BAD + angleBCD = 1/2 Angle BOD + 1/2 Angle DOB

= 1/2 (AngleBOD + angle DOB)

= 1/2 ×360

=180

Same as

angle B + angleD = 180

Answer 2

Answer:

hey mate ❤

Step-by-step explanation:

Proof - OB & OD

angleBOD = angle2BOD

angleBAD = angle1/2 BOD

Same as

angleBCD = angle1/2 DOB

angle BAD + angleBCD = 1/2 Angle BOD + 1/2 Angle DOB

= 1/2 (AngleBOD + angle DOB)

= 1/2 ×360

=180

Same as

angle B + angleD = 180