Question

prove that the sum of the square of the side of a rhombus is equal to the sum of the square of its diagonal​

Answer 1

Given :- A rhombus ABCD whose diagonals AC and BD intersect at O.

To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ).

Proof :

Refer attachment pls

In a rhombus , all sides are equal

Hence, it is proved.