Question

prove that the sum of the square of the side of the Rhombus is equal to the same of its square of its diagonals​

Answer 1

Answer:

In rhombus ABCD, AB = BC = CD = DAWe know that diagonals of a rhombus bisect each other perpendicularly.That is AC ⊥ BD, ∠AOB=∠BOC=∠COD=∠AOD=90° andConsider right angled triangle AOBAB2= OA2+ OB2 [By Pythagoras theorem]⇒ 4AB2= AC2+ BD2⇒ AB2+ AB2+ AB2+ AB2= AC2+ BD2∴ AB2+ BC2+ CD2+ DA2= AC2+ BD2Thus the sum of the squares of the sides of a rhombus is equal to the sum of the squares of its diagonals.

Answer 2

Answer:

Coonit know

Step-by-step explanation:

Candidate should be belong to the party quanguo renmin daibiao dahui ( national people's Congress )..

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