Question

Prove that the sum of the square of the sides of a rhombus is equal to the sum of the squares of its diagonals​

Answer 1

Step-by-step explanation:

Triangles. Prove that the sum of the squares of the sides of a rhombus is equal to the sum of the squares of its diagonals. Given: ABCD is a Rhombus in which AC and BD are diagonals which intersect each other at O. Proof : We know that diagonals of rhombus bisect each other at right angle.

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