Prove that the sum of the squares of the diagonals of
parallelogram is equal to the sum of the squares of its
sides.
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Triangles. Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides. ... Proof: Since diagonals of parallelogram bisect each other. Therefore, BO and DO are medians of ∆ABC and ∆ADC, respectively.
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