Question

Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of

its sides.​

Answer 1

Step-by-step explanation:

you can understand it by an example

O is the mid point of AC and BD. In ∆ABD, point O is the midpoint of side BD. In ∆CBD, point O is the midpoint of side BD. Hence, the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.

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Answer 2

Step-by-step explanation:

Draw perpendiculars from C and D on AB as shown. Thus the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides

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