Prove that the sum of three angles of a triangle is 180°.
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draw a line XY passing through A parellel to BC
angle ABC = angle XAB ( alternate interior angles)
angle ACB = angle YAC ( alternate interior angles)
angle XAB + angle YAC + angle A = 180 degrees ( straight angle)
angle ABC + angle ACB + angle A = 180 degree
hence proved
angle ABC = angle XAB ( alternate interior angles)
angle ACB = angle YAC ( alternate interior angles)
angle XAB + angle YAC + angle A = 180 degrees ( straight angle)
angle ABC + angle ACB + angle A = 180 degree
hence proved
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angles of triangle = 180 degrees
so all the sides of the triangle will be xcm
=> x+x+x=180
=>3x=180
=>x=180/3
=>x=60 degrees
so now if we will add 60 three times then the sum will be 180 degrees
so now pls make it brainliest
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