Question

prove that the sum of three attitude of a triangle is less than sum of the three side of the triangle.
with figure​

Answer 1

Step-by-step explanation:

Let ABC be tge triangle

draw the perpendicular AD,BE and CF from A B C to opposite sides meeting sides BC AC and AB at D. E. F.

now perpendicular AD^2=AC^2-CD^2===

AD^2. < AC^2 or

AD^2 < AC

or AD <b-------------(1)

also BE^2=AB^2 -AE^2

====BE^2. < AB^2OR BE<AB

or BE<c---------------(2)

likewise , CF^2 =BC^2 -BF^2

=====CF^2 <BC^2 or CF<Bc

or CF<a------------------(3)

adding inequalities (1),(2),(3),AD+BE+CF<a+b+c

hope it will help you G.P

BY ....ADITI SRIII