prove that the sum of three exterior angle of a triangle formed by producing the sides in order angle is 4 angle or 360 degree
Answers
To prove:
The sum of three exterior angle of a triangle formed by producing the sides in order angle is 4 right angles or 360°.
Proof:
Let ABC is a triangle.
In Δ ABC,
- x, y and x are exterior angles.
- a, b and c are interior angles.
As we know that the exterior angle of a triangle are equal to the sum of the two opposite interior angles, therefore-
- x = b+c
- y = a+c
- z = a+b
So,
x+y+z = (b+c)+(a+c)+(a+b)
or, x+y+z = b+c+a+c+a+b
or, x+y+z = a+a+b+b+c+c
or, x+y+z = 2a+2b+2c
or, x+y+z = 2(a+b+c)
As we know that the sum of all interior angles of a triangle is 180°, therefore-
x+y+z = 2(a+b+c)
or, x+y+z = 2(180)
or, x+y+z = 2×180
or, x+y+z = 360
So, x+y+z = 360° = 4 right angles
Proved:
The sum of three exterior angle of a triangle formed by producing the sides in order angle is 4 right angles or 360°.
Hope this helps you to get to your answer.
Answer:
In ABC , By Angle sum property of triangle,
ABC + BAC + BC A =180°-------(1)
Now, By linear pair property
1 + BAC = 180° ---------(2)
And 2 + ABC = 180° ---------(3)
And 3 + BCA = 180° ---------(4)Add equation (2) (3) and (4)
1 +BAC+2+ABC+3+BCA= 180°+180°+180°
1+2 +3 + BAC+ABC+BCA = 540°
1+2 +3 + 180° = 540° (from eq 1)
1+2 +3 = 540° - 180°
1+2 +3 = 360°
Hence, it is proved that sum exterior angle of triangle is 360°