Question

prove that the sum of two consecutive angles of a parallelogram is 180 degree

Answer 1

Let ABCD be a llgm with angles a,b,c and d

So we that in a llgm opp angles are equal (1)

So,

a+b+c+d=360.(As llgm isQuadrilateral)

Let a and d be opp angles and a,b and c,d be consecutive angles

2a +2b =360°. [by (1)]

a+b=360/2=180°

Hence proved

Answer 2

Answer:

very easy question answer is 180

In a parallelogram prove that sum of any two consecutive angles is 180 degrees

Since is a parallelogram,

Now, and transversal intersects them at and respectively.

Sum of the interior angles on the same side of the transversal is

Since is a parallelogram,

Now, and transversal intersects them at and respectively.

Sum of the interior angles on the same side of the transversal is

Now, and transversal intersects them at and respectively.

Sum of the interior angles on the same side of the transversal is

Now, and transversal intersects them at and respectively.

Sum of the interior angles on the same side of the transversal is

Hence proved.