Question

Prove that the sum of two sides of as N atriangle greater than twice the median

Answer 1

Given : Triangle ABC in which AD is the median.
To prove:AB+AC>2AD
Construction :

Extend AD to E such that AD=DE .
 Now join EC.

Proof:
In ΔADB and ΔEDC
AD=DE[ By construction]
D is the midpoint BC.[DB=DB]

ΔADB=ΔEDC [vertically opposite angles]

Therefore Δ ADB ≅  ΔEDC [ By SAS congruence criterion.]
--> AB=ED[Corresponding parts of congruent triangles ]
In ΔAEC,
AC+ED> AE [sum of any two sides of a triangle is greater than the third side]
AC+AB>2AD[AE=AD+DE=AD+AD=2AD and ED=AB]