prove that the sumo interior angles of a triangle is 180
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considering in triangle abc.
bc is the base.
draw a line pq parallel to bc.
angle b= angle pab.
angle c=angle qac.
pab+pac+a= 180
b+c +a= 180.
bc is the base.
draw a line pq parallel to bc.
angle b= angle pab.
angle c=angle qac.
pab+pac+a= 180
b+c +a= 180.
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