prove that the surface area of a sphere is equal to the curved surface area of the circumsceibed cylinder .plz. ans .fast
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surface area of sphere is 4piarsquare
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answer:-
surface area of sphere=4πr^2
C.S.A of cylinder=2πrh
S.A of sphere = C.S.A of cylinder
4πr^2 = 2πrh
4/2 ×π × r × r= π × r ×h
2r=h
C.S.A of cylinder= 2πrh
put h=2r in C.S.A of cylinder
= 2×π×r×2×r
4πr^2
hence proved,surface area of sphere is equal to the curved surface area of cylinder.
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